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Check if the input number is a Amstrong number or not


Code ResourceAuthor: Jimmy Zorald  

Difficulty Level:

Published: 25th May 2007   Read: 6276 times  

Filed in: C
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This is a very simple code that checks if a number is a Amstrong number or not. This is mostly useful for beginners who are starting to learn C programming.

 


Sample Code
  1.  
  2. #include <stdio.h>
  3. #include <stdlib.h>
  4. #include <string.h>
  5. #include <math.h>
  6.  
  7. void main()
  8. {
  9.         long num1,num2=0,mcount=0, nums;
  10.         char str1[35], strc;
  11.  
  12.         clrscr();
  13.         printf("Enter a number : ");
  14.         scanf("%ld",&num1);
  15.  
  16.          ltoa(num1,str1,10);
  17.          while (mcount <= (strlen(str1)-1))
  18.          {
  19.           strc = str1[mcount];
  20.           nums = atoi(&strc);
  21.           num2 = num2+pow(nums,3);
  22.           mcount = mcount+1;
  23.          }
  24.  
  25.          if (num1 == num2)
  26.          {
  27.           printf("Amstrong Number : %ld",num2);
  28.          }
  29.          else
  30.          {
  31.           printf("Not a Amstrong Number.");
  32.          }
  33.    getch();
  34. }
  35.  
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